Subject: RE: [xsl] XPath for number of preceding nodes sharing an ancestor From: "Michael Kay" <mhkay@xxxxxxxxxxxx> Date: Wed, 16 May 2001 04:15:16 +0100 |
> > You really need a set intersection here; if you don't want to use an > > extension function there's the $x[count(.|$y)=count($y)] trick. > > Will you please elaborate? I don't understand the 'trick'. > What are the > values of $x and $y? If $x and $y are node-sets, then $x[count(.|$y)=count($y)] contains those nodes that are in both $x and $y. > Also, could I use: > > count(preceding::input[generate-id(ancestor::inputform) = > generate-id(current()/ancestor::inputform)]) No, because generate-id() applied to a node-set returns the id of the first node in the node-set, considered in document order. Mike Kay XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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