[xsl] contains()???

["Gitanjali" <narsu@xxxxxxxxxxxxx>]

All,

Could you please solve my problem.  Acutally I passed the parameter from the
html as id = "1002,1003,1004"

Now I want to display only those records where parameter id matches the
input .  The following xsl is not working...It's displaying all the results.

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  <xsl:output method="html" indent="no" />
  <xsl:param name="id" select="1003" />

  <xsl:template match="addresses">
 <xsl:value-of select="$id"/>
 <xsl:if test="contains(string(emp[@id]),string($id))"> </xsl:if>
     <xsl:apply-templates select="emp"/>
 <xsl:if test="contains(string(emp[@id]),string($id))"> </xsl:if>
  </xsl:template>

  <xsl:template match="emp">
    <h1>Name: <xsl:value-of select="concat(details/@fname, ' ',
details/@lname)" /></h1>
    <p>Email: <a href="mailto:{email}";><xsl:value-of select="email"
/></a><br />
    Country: <xsl:value-of select="details/@country" /><br />
 Phone: <xsl:value-of select="details/@phone" />
    </p>
  </xsl:template>
</xsl:stylesheet>


My xml file is :

<addresses>
 <emp registered="20010125" id="1001">
  <email>scott@xxxxxxxxxx</email>
  <details fname="Scott" lname="Wilson" country="UK" phone="1800callme"/>
 </emp>
 <emp registered="20010125" id="1002">
  <email>john@xxxxxxxx</email>
  <details fname="John" lname="Kerr" country="USA" phone="1800callJohn"/>
 </emp>
 <emp registered="20010125" id="1003">
  <email>kim@xxxxxxxxx</email>
  <details fname="Kimberly" lname="Chung" country="USA"
phone="1800callKim"/>
 </emp>
 <emp registered="20010125" id="1004">
  <email>Tim@xxxxxxxxxx</email>
  <details fname="Timmothy" lname="Kelley" country="USA"
phone="1800callTim"/>
 </emp>
 <emp registered="20010125" id="1005">
  <email>Marie@xxxxxxxxxxxx</email>
  <details fname="Marie" lname="Whitaker" country="AU"
phone="1800callMarie"/>
 </emp>
</addresses>



Thanks
Narsu


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list