Re: [xsl] contains()???

["Gitanjali" <narsu@xxxxxxxxxxxxx>]

Thanks a lot Jason,

Great!  Whatever the output I'm expecting, U gave me.  Thanks for your clear
explaination about my problem.

Thanks again!

Narsu



----- Original Message -----
From: "Diamond, Jason" <Jason.Diamond@xxxxxxx>
To: <xsl-list@xxxxxxxxxxxxxxxxxxxxxx>
Sent: Tuesday, May 15, 2001 9:45 PM
Subject: RE: [xsl] contains()???


> You're not too clear on what you're trying to achieve. Do you only want to
> output the employees that have id attributes listed in the id parameter?
If
> so, there's a number of problems that I can see in your transform and
> they're all contribute to the results your getting. I'll list them off as
in
> the order I noticed them.
>
> Firstly, the first parameter to contains() is not what I think you think
it
> is. The innermost expression, emp[@id], is selecting all emp elements that
> have an id attribute--not all the id attributes on the emp elements.
You're
> converting those elements into a string and testing to see if that string
> contains the id. The string value of an emp element only contains an email
> address and some whitespace. I think that you want to use emp/@id instead
> which will select all of the id attributes on all of the emp elements.
>
> Also, if $id can contain comma separated IDs then you probably want to
> switch the order in which you pass in your parameters. The contains()
> function only returns true when the string value of the first parameter
> contains the string value of the second parameter. Since your example
source
> document has id attributes that contain only single IDs, it will never be
> true that they will contain a string like "1002,1003,1004" but it could be
> true the other way around.
>
> More importantly, your xsl:if statements aren't even doing anything.
They're
> both empty. The instructions that you want to execute if a certain
condition
> is true need to be children of xsl:if. You have an xsl:apply-templates
> between--not inside--two empty if statements so the apply-templates will
> always happen.
>
> And the final reason for why you're outputting everybody is that your
> xsl:apply-templates isn't using a predicate. Without a predicate (the part
> in square brackets), it will select all emp child elements of the current
> node. It should probably be something like this:
>
> <xsl:apply-templates select="emp[contains($id, @id)]"/>
>
> This will select all emp children who's id attribute is "contained" by the
> $id parameter.
>
> I've made this change and cut out some of the dead code (as far as I can
> reason) and the stylesheet now looks like this:
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>   <xsl:output method="html" indent="no"/>
>   <xsl:param name="id" select="1003" />
>
>   <xsl:template match="addresses">
>     <xsl:apply-templates select="emp[contains($id, @id)]"/>
>   </xsl:template>
>
>   <xsl:template match="emp">
>     <h1>Name: <xsl:value-of select="concat(details/@fname, ' ',
> details/@lname)" /></h1>
>     <p>Email: <a href="mailto:{email}";><xsl:value-of select="email"
> /></a><br />
>     Country: <xsl:value-of select="details/@country" /><br />
>  Phone: <xsl:value-of select="details/@phone" />
>     </p>
>   </xsl:template>
> </xsl:stylesheet>
>
> Running this on your example without specifying a value for id results in
> only Kimberly Chung being output. Is that what you expected?
>
> Jason.
>
> -----Original Message-----
> From: Gitanjali [mailto:narsu@xxxxxxxxxxxxx]
> Sent: Tuesday, May 15, 2001 5:59 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: [xsl] contains()???
>
>
> All,
>
> Could you please solve my problem.  Acutally I passed the parameter from
the
> html as id = "1002,1003,1004"
>
> Now I want to display only those records where parameter id matches the
> input .  The following xsl is not working...It's displaying all the
results.
>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
>   <xsl:output method="html" indent="no" />
>   <xsl:param name="id" select="1003" />
>
>   <xsl:template match="addresses">
>  <xsl:value-of select="$id"/>
>  <xsl:if test="contains(string(emp[@id]),string($id))"> </xsl:if>
>      <xsl:apply-templates select="emp"/>
>  <xsl:if test="contains(string(emp[@id]),string($id))"> </xsl:if>
>   </xsl:template>
>
>   <xsl:template match="emp">
>     <h1>Name: <xsl:value-of select="concat(details/@fname, ' ',
> details/@lname)" /></h1>
>     <p>Email: <a href="mailto:{email}";><xsl:value-of select="email"
> /></a><br />
>     Country: <xsl:value-of select="details/@country" /><br />
>  Phone: <xsl:value-of select="details/@phone" />
>     </p>
>   </xsl:template>
> </xsl:stylesheet>
>
>
> My xml file is :
>
> <addresses>
>  <emp registered="20010125" id="1001">
>   <email>scott@xxxxxxxxxx</email>
>   <details fname="Scott" lname="Wilson" country="UK" phone="1800callme"/>
>  </emp>
>  <emp registered="20010125" id="1002">
>   <email>john@xxxxxxxx</email>
>   <details fname="John" lname="Kerr" country="USA" phone="1800callJohn"/>
>  </emp>
>  <emp registered="20010125" id="1003">
>   <email>kim@xxxxxxxxx</email>
>   <details fname="Kimberly" lname="Chung" country="USA"
> phone="1800callKim"/>
>  </emp>
>  <emp registered="20010125" id="1004">
>   <email>Tim@xxxxxxxxxx</email>
>   <details fname="Timmothy" lname="Kelley" country="USA"
> phone="1800callTim"/>
>  </emp>
>  <emp registered="20010125" id="1005">
>   <email>Marie@xxxxxxxxxxxx</email>
>   <details fname="Marie" lname="Whitaker" country="AU"
> phone="1800callMarie"/>
>  </emp>
> </addresses>
>
>
>
> Thanks
> Narsu
>
>
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>
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