Subject: RE: [xsl] Using xsl:sort to sort negative values From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Wed, 21 Feb 2007 09:33:49 -0000 |
> Can anyone tell why the code below will not work? > > <xsl:sort select="data" data-type="number"/> > > I am trying to sort numeric data that contains negative > values but the order seems to be wrong > > <xml> > <data>22</data> > <data>2</data> > <data>-5</data> > <data>42</data> > <data>0</data> > <data>-1</data> > <data>0</data> > </xml> If data selects anything, then it will select 7 child elements of <xml>, and a sort key consisting of a sequence of 7 elements is unlikely to be useful. Chances are you want <xsl:for-each select="data"> <xsl:sort select="." data-type="number"/> Incidentally, element names beginning with "xml" are reserved for future standardization, therefore best avoided. Michael Kay http://www.saxonica.com/
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