Re: [xsl] Using xsl:sort to sort negative values

[Abel Braaksma <abel.online@xxxxxxxxx>]

Hi Sola,

You didn't show your full code and you didn't tell what processor you 
are using and what XSLT version. If you specifiy "number" for the 
data-type, then the content is converted to a numeric value. This 
includes the minus sign.

Note that your data is illegal XML as where legal XML it is not allowed 
to have any element starting with xml, XML or any combination of case, 
see http://www.w3.org/TR/xml/#IDAKKFS. However, most XML processors dig 
it anyway ;)

I tried the following stylesheet and ran it with Saxon 8. It gives the 
result you want:

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
  
   <xsl:output indent="yes" />
  
   <xsl:template match="/xml">
       <xsl:apply-templates select="data">
          <xsl:sort select="." data-type="number" />
       </xsl:apply-templates>
   </xsl:template>
  
   <xsl:template match="data">
       <xsl:text>&#10;</xsl:text>
       <xsl:value-of select="text()"/>
   </xsl:template>
  
</xsl:stylesheet>


If this does not work with your processor, it is likely a bug.

Good luck with it,

Cheers,
-- Abel



Sola Awe wrote:
> Hi,
>   Can anyone tell why the code below will not work?
>
> <xsl:sort select="data" data-type="number"/>
>
> I am trying to sort numeric data that contains negative values but the 
> order seems to be wrong
>
> <xml>
> <data>22</data>
> <data>2</data>
> <data>-5</data>
> <data>42</data>
> <data>0</data>
> <data>-1</data>
> <data>0</data>
> </xml>
>
>
> This is the output
>
> 0
> -1
> 0
> -5
> 2
> 22
> 42
>
> I want
> -5
> -1
> 0
> 0
> 2
> 22
> 42