Subject: RE: [xsl] only display if subnodes occur more than once From: "Andrew Welch" <ajwelch@xxxxxxxxxxxxxxx> Date: Thu, 23 Jun 2005 13:27:45 +0100 |
I wrote: > <xsl:template match="sub_a|sub_b|sub_c"> > <xsl:variable name="copy" > select="boolean(*/following-sibling::*[local-name() = > preceding-sibling::*/local-name()])"/> > > <xsl:if test="$copy"> > <xsl:copy-of select="."/> > </xsl:if> > </xsl:template> ...which relies on the slash operator in 2.0. A 1.0 solution that I've cobbled together quickly is: <xsl:template match="sub_a|sub_b|sub_c"> <xsl:variable name="copy"> <xsl:for-each select="*"> <xsl:if test="following-sibling::*[local-name() = local-name(current())]">true</xsl:if> </xsl:for-each> </xsl:variable> <xsl:if test="contains($copy, 'true')"> <xsl:copy-of select="."/> </xsl:if> </xsl:template> (Not very good)
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