Subject: [xsl] only display if subnodes occur more than once From: "Prerovsky, Clemens" <Clemens.Prerovsky@xxxxxxx> Date: Thu, 23 Jun 2005 12:06:42 +0200 |
Hi, I'm stuck again with my XSL. My XML Structure looks like: <root> <sub_a> <elem_1/> <elem_2/> <elem_3/> </sub_a> <sub_b> <elem_1/> <elem_2/> <elem_2/> <elem_2/> <elem_3/> </sub_b> <sub_c> <elem_1/> <elem_2/> <elem_3/> </sub_c> </root> The thing I want to do is display the element sub_b, because it has subnodes which occur more than once (elem_2). I really have no idea how to test for this - playing around for nearly two hours now. Im using a loop like <xsl:for-each select="/root/*"> and the output should look like sub_b (this is the header) elem_2 elem_2 (these are the 3 values of elem_2) elem_2 Best regards, Clemens Prerovsky
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