Subject: RE: [xsl] combining the children of similar nodes under one node From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Sun, 7 Mar 2004 11:40:51 +0100 |
> -----Original Message----- > From: David Montalvo > <snip /> > One of the problems is that <style> and <type> are being used > interchangeably, but I think I compensated for that. My big problem is > getting everything listed under one name with no duplicates. > Hi, Sounds like a grouping-problem... Try something like: <xsl:stylesheet ...> <xsl:key name="prods-by-name" match="product" use="name" /> <xsl:key name="style-type-by-prod" match="style | type" use="concat(parent::product/name,.)" /> <xsl:variable name="distinct-prods" select="//product[generate-id(.)=generate-id( key('prods-by-name',name))]" /> <xsl:template match="root"> <xsl:apply-templates select="$distinct-prods" mode="merge"/> </xsl:template> <xsl:template match="product" mode="merge"> <xsl:copy> <xsl:copy-of select="name" /> <xsl:apply-templates select="key('prods-by-name',name)" mode="list" /> </xsl:copy> </xsl:template> <xsl:template match="product" mode="list"> <xsl:apply-templates select="(style | type)[generate-id(.)=generate-id( key('style-type-by-prod',concat( current()/name,.)))]" /> </xsl:template> <xsl:template match="style | type"> <xsl:copy-of select="." /> </xsl:template> </xsl:stylesheet> Hope this helps! Cheers, Andreas XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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