[xsl] combining the children of similar nodes under one node

[David Montalvo <damontal@xxxxxxxxxxx>]

in the following example code, notice that all three nodes have the 
same name. I want to combine all nodes with the same name into one node 
with all of their <style>s and <types>s, where <style> and <type> are 
not duplicated.

<inventory>
	<product>
		<name>chair</name>
		<style>rocking</style>
	</product>

	<product>
		<name>chair</name>
		<type>rocking</type> --> same value as <style> above
	</product>
	<product>
		<name>chair</name>
		<style>folding</style>
		<type>lawn</type>
	</product>
</inventory>

When I'm in the first node, I grab it, when I'm in the second node, I 
can check the preceding <style> value and skip it, when I'm in the 
third node I grab it. That gives me:

	<product>
		<name>chair</name>
		<style>rocking</style>
	</product>
	<product>
		<name>chair</name>
		<style>folding</style>
		<type>lawn</type>
	</product>

I figured out that, while in the second of these nodes, I can check if 
the preceding name is the same and, if so, get the preceding <style> 
and add it to the second product node, giving me:

	<product>
		<name>chair</name>
		<style>rocking</style>
	</product>
	<product>
		<name>chair</name>
		<style>rocking</style>
		<style>folding</style>
		<type>lawn</type>
	</product>

but I still have 2 products with the name "chair". how can I get the 
result:

	<product>
		<name>chair</name>
		<style>rocking</style>
		<style>folding</style>
		<type>lawn</type>
	</product>

One of the problems is that <style> and <type> are being used 
interchangeably, but I think I compensated for that. My big problem is 
getting everything listed under one name with no duplicates.

-dave




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