Subject: Re: [xsl] displaying a list in a multi-column table From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Fri, 25 Jan 2008 14:04:38 +0000 |
On 25/01/2008, Michael Tracey Zellmann <tracey.zellmann@xxxxxxxxx> wrote: > I have a list of words, possibly 3500 to 7000 in length, in > alphabetical order. I need to display them in an HTML page in a table > of four columns. The first quarter of the words should be in the first > column, the second quarter in the second column, etc. Since the total > may not be divisible by four, the final column may be incomplete. > Let's say the input is of the form: > <wordList> > <word>aaron</word> > <word>abated</word> > <word>abatement</word> > .. > </wordList> > > How can I do this with an XSLT transform? > > I can use XSLT 2.0 That's good... in which case you can do: <xsl:for-each-group select="$wordlist" group-starting-with="*[position() mod 4 = 1]"> <tr> <xsl:for-each select="current-group()"> <td><xsl:value-of select="."/></td> </xsl:for-each> </tr> </xsl:for-each-group> cheers -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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