Subject: Re: [xsl] xpath query From: "Sean Tiley" <sean.tiley@xxxxxxxxx> Date: Fri, 18 Jan 2008 18:46:22 -0500 |
Hi there, I am still struggling with mostof this stuff, but I have a question related to the original data. <ROOT> <LEVEL2> <B> <a>100</a> <b apply="1">100</b> <c>100</c> </B> <C> <a>100</a> <b>100</b> <c apply="1">100</c> </C> </LEVEL2> </ROOT> If I create the following stylesheet I get 100 100 output <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="2.0"> <xsl:template match="ROOT"> <html> <xsl:value-of select="LEVEL2/*/*[@apply='1']"/> </html> </xsl:template> </xsl:stylesheet> What I am not clear on is why does this return values and not nodes? Or is this really returning both nodes and I am getting the value of each one because of the <xsl:value-of select="..."/> expression? As far as I can figure the expression ROOT/LEVEL2/*/*[@apply='1']" says give me the nodes that have the arrtibute apply=1 and are grandchildren of level2. I kind of though to get both values I would have to do something like <xsl:template match="ROOT"> <xsl:for-each select="LEVEL2/*/*[@apply='1']"> <xsl:value-of select="."/> </xsl:for-each> </xsl:template> Sorry if this seems really trivial but it helps me to better understand. -- Thanks Sean
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