Subject: RE: [xsl] XSLT - How to find the last element in a group of nodes inside of a for loop From: "Chaudhary, Harsh" <HCHAUDHA@xxxxxxxxx> Date: Thu, 17 Jan 2008 14:02:20 -0600 |
Worked like a charm. Thanks a lot. Funnily enough, I know about both the position and the last functions, just never put em together. Harsh. -----Original Message----- From: Wendell Piez [mailto:wapiez@xxxxxxxxxxxxxxxx] Sent: Thursday, January 17, 2008 1:46 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: Re: [xsl] XSLT - How to find the last element in a group of nodes inside of a for loop Harsh, At 02:10 PM 1/17/2008, you wrote: ><xsl:for-each select="//competitor[generate-id() = >generate-id(key('someKey', @zone))]"> > > <xsl:sort select="@zone"/> > <xsl:for-each select="key('someKey', @zone)"> > > <xsl:sort select="@competitorTerritory"/> > //Some code > > //How do I detect the last row for each Zone? Since you're iterating over all the competitor nodes with a given zone, you can use position() to identify particular nodes within the iteration. So here, what you want should be <xsl:if test="position() = last()"> ... do your thing </xsl:if> Of course, I don't know what other complications there might be. Cheers, Wendell ====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. http://www.mulberrytech.com 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================
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