Subject: Re: [xsl] Return value from a template... From: "Eric Bréchemier" <eric.brechemier@xxxxxxxxx> Date: Tue, 8 Jan 2008 17:53:43 +0100 |
Hi Batis, You cannot use call-template with select="/root/bib" "Unlike xsl:apply-templates, xsl:call-template does not change the current node or the current node list." [1] You should give a try to using apply-templates instead. Besides, "variable" in XSLT cannot be changed after first initialization, so <xsl:variable name="var" select="concat($var,ids, $delimiter)"/> is bound to fail. [1] XSL Transformation (XSLT) version 1.0, '6 Named Templates http://www.w3.org/TR/xslt#named-templates Cheers, Eric Brichemier On Jan 8, 2008 4:58 PM, Batis DAVE <batis.04@xxxxxxxxx> wrote: > I want to return a variable value from a template based on this example: > http://biglist.com/lists/xsl-list/archives/200205/msg01614.html > but it's not working... > Here's my code: > <?xml version="1.0"?> > <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> > <xsl:output indent="yes" method="html" omit-xml-declaration="no" > encoding="ISO-8859-1" /> > <xsl:param name="delimiter" select="','"/> > > <xsl:template match="/root"> > > <xsl:variable name="idList"> > <xsl:call-template select="/root/bib" name="getIdList" /> > </xsl:variable> > > <xsl:value-of select="$idList"/> > > </xsl:template> > > > <xsl:template match="/root/bib" name="getIdList"> > <xsl:for-each select="/root/bib"> > <xsl:variable name="var" select="concat($var,ids, $delimiter)"/> > </xsl:for-each> > <xsl:value-of select="$var"/> > </xsl:template> > > </xsl:stylesheet> > > What's wrong in it?
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Return value from a templ, Martin Honnen | Thread | [xsl] Not able to render image gene, Charanpreet Arora |
Re: [xsl] Return value from a templ, Martin Honnen | Date | Re: [xsl] Sorting and Grouping Alph, David Carlisle |
Month |