Subject: RE: [xsl] selecting a node to concatenate From: cknell@xxxxxxxxxx Date: Thu, 04 Oct 2007 13:44:01 -0400 |
Assuming your concats and substrings are correct, you want to create a template to match "submissionDeadline" and apply the template from your stylesheet at the appropriate point. Replace $currentTime with ".", which represents the current node. <xsl:template match="submissionDeadline"><xsl:value-of select="concat(substring(., ,4),substring(.,6,2),substring(.,9,2),substring(.,12,2),substring (.,15,2),substring.,18,2))"/></xsl:template> -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: Aaron Johnson <artpunx@xxxxxxxxx> Sent: Thu, 4 Oct 2007 18:25:39 +0100 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] selecting a node to concatenate I have a node in my XML which contains a date string. I want to concatenate it into an integer. I can do the concat part using substrings but can't work out how to select the node in the first instance! The XML looks like this... 2027-10-04T09:00:00.0000000-00:00</submissionDeadline> ..if I pass it to the stylesheet as a param or variable I can concatanate it... <xsl:variable name="currentTime">2007-10-04T09:00:00.0000000+01:00</xsl:variable> <xsl:variable name="currentTimeString" select="concat(substring($currentTime, 1,4),substring($currentTime, 6,2),substring($currentTime, 9,2),substring($currentTime,12,2),substring($currentTime,15,2),substring($currentTime,18,2))"/> .. to make it look like this... 20071004090000 I need a way to select the <submissionDeadline> nodes content to get a similar result. Any ideas? Thanks for any suggestions...
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