Subject: Re: [xsl] XSLT/XPath Question (Grouping Authors by First Character of Last Name) From: "Dimitre Novatchev" <dnovatchev@xxxxxxxxx> Date: Sat, 3 Mar 2007 14:25:09 -0800 |
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="text"/>
<xsl:template match="/"> <xsl:for-each-group select="*/author" group-by="substring(name/@file-as,1,1)" > <xsl:text>

</xsl:text> <xsl:value-of select="current-grouping-key()"/> <xsl:text>
</xsl:text>
<xsl:for-each select="current-group()"> <xsl:value-of select="name/@file-as"/> <xsl:text>
</xsl:text> </xsl:for-each> </xsl:for-each-group> </xsl:template> </xsl:stylesheet>
A Adams, Douglas Anderson, Kevin J. Anthony, Piers Archer, Jeffrey
B Baldacci, David Ball, Margaret Bradley, Marion Zimmer
C Carcaterra, Lorenzo Card, Orson Scott Chalker, Jack L.
D Dahl, Roald Daley, Brian Dann, Jack
-- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play
I have an XSLT/XPath Question that I've been beating my head against for a while.
I have a list of authors with a name element and a file-as attribute (XPATH: /booklist/author/name/@file-as). I currently build a Table of Contents sorted by the author/name/@file-as attribute. That works OK. I want to add further markup (by putting authors in groups by the first character of their last name).
I can get the first character of the last name, I've even created a key that allows me to access the nodes of authors by the first character in the last name (see the commented out section of the b.xsl file included below). However, I can not figure out how to get a list of distinct characters (from the last names) so that I can iterate over them and generate my list.
Here are stripped down example source files:
Exmaple author file: (file a.xml)
<?xml version="1.0" encoding="UTF-8"?> <booklist> <author> <name file-as="Adams, Douglas">Douglas Adams</name> </author> <author> <name file-as="Anderson, Kevin J.">Kevin J. Anderson</name> </author> <author> <name file-as="Anthony, Piers">Piers Anthony</name> </author> <author> <name file-as="Archer, Jeffrey">Jeffrey Archer</name> </author> <author> <name file-as="Baldacci, David">David Baldacci</name> </author> <author> <name file-as="Ball, Margaret">Margaret Ball</name> </author> <author> <name file-as="Bradley, Marion Zimmer">Marion Zimmer Bradley</name> </author> <author> <name file-as="Carcaterra, Lorenzo">Lorenzo Carcaterra</name> </author> <author> <name file-as="Card, Orson Scott">Orson Scott Card</name> </author> <author> <name file-as="Chalker, Jack L.">Jack L. Chalker</name> </author> <author> <name file-as="Dahl, Roald">Roald Dahl</name> </author> <author> <name file-as="Daley, Brian">Brian Daley</name> </author> <author> <name file-as="Dann, Jack">Jack Dann</name> </author> </booklist>
I can extract the authors and generate a table of contents with the following XSLT: (b.xsl)
<?xml version="1.0"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="xml"/> <xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:key name="alet" match="//author" use="substring(name/@file-as,1,1)"/>
<xsl:template match="/booklist"> <xsl:call-template name="gen-toc"/> </xsl:template>
<!-- Generate Table of Contents --> <xsl:template name="gen-toc"> <div id="toc" class="toc"> <!-- <h1>Test</h1> <ul> <xsl:for-each select="key('alet','A')"> <li><xsl:value-of select="name/@file-as"/></li> </xsl:for-each> </ul> --> <h1>Table of Contents (by Author)</h1> <ul> <xsl:for-each select="//author/name"> <xsl:sort select="@file-as"/> <li><a href="#{generate-id(..)}"><xsl:value-of select="@file-as"/></a></li> </xsl:for-each> </ul> </div> </xsl:template>
</xsl:stylesheet>
This works. It generates this: (out.xml)
<?xml version="1.0"?> <div id="toc" class="toc"> <h1>Table of Contents (by Author)</h1> <ul> <li> <a href="#id91524">Adams, Douglas</a> </li> <li> <a href="#id91570">Anderson, Kevin J.</a> </li> <li> <a href="#id91578">Anthony, Piers</a> </li> <li> <a href="#id91588">Archer, Jeffrey</a> </li> <li> <a href="#id91597">Baldacci, David</a> </li> <li> <a href="#id91607">Ball, Margaret</a> </li> <li> <a href="#id91617">Bradley, Marion Zimmer</a> </li> <li> <a href="#id91627">Carcaterra, Lorenzo</a> </li> <li> <a href="#id93622">Card, Orson Scott</a> </li> <li> <a href="#id93633">Chalker, Jack L.</a> </li> <li> <a href="#id93643">Dahl, Roald</a> </li> <li> <a href="#id93653">Daley, Brian</a> </li> <li> <a href="#id93663">Dann, Jack</a> </li> </ul> </div>
I want to change that so that I have the authors in subsections, with the first letter of their last names as the the main entry, like so
A //author/name/@file-as[.=='A'] B //author/name/@file-as[.=='B'] etc..
Like this output: (out-desired.xml)
[This was hand edited, I have not yet figured out how to automatically generate it.]
<?xml version="1.0"?> <div id="toc" class="toc"> <h1>Table of Contents (by Author)</h1> <ul> <li> <a name="A">A</a> <ul> <li> <a href="#id91524">Adams, Douglas</a> </li> <li> <a href="#id91570">Anderson, Kevin J.</a> </li> <li> <a href="#id91578">Anthony, Piers</a> </li> <li> <a href="#id91588">Archer, Jeffrey</a> </li> <li> <a href="#id91597">Baldacci, David</a> </li> </ul> </li> <li> <a name="B">B</a> <ul> <li> <a href="#id91607">Ball, Margaret</a> </li> <li> <a href="#id91617">Bradley, Marion Zimmer</a> </li> </ul> </li> <li> <a name="C">C</a> <ul> <li> <a href="#id91627">Carcaterra, Lorenzo</a> </li> <li> <a href="#id93622">Card, Orson Scott</a> </li> <li> <a href="#id93633">Chalker, Jack L.</a> </li> </ul> </li> <li> <a name="D">D</a> <ul> <li> <a href="#id93643">Dahl, Roald</a> </li> <li> <a href="#id93653">Daley, Brian</a> </li> <li> <a href="#id93663">Dann, Jack</a> </li> </ul> </li> </ul> </div>
I've tried some XPath 2 stuff and XQuery. I can get a list of first letters using XQuery (and thus XPath 2)
For example: (file fl.xq)
for $a in //author/name/substring(@file-as,1,1) return <c>{$a}</c>
Generates a list of the characters of the last name (although not unique).
I tried embedding something like the above "for $a in.." into an XSLT 2.0 stylesheet, and assign it to a variable, but I get an error from saxon when I tried it.
Something like this is desired.... (with UNIQUE-SET-OF-FIRST-LETTERS) replaced with something that works. I set this to XSLT 2, and tried "$letters//l" in place of that place-holder text (UNIQUE-SET-OF-FIRST-LETTERS). It generated the Letter items A B C .., but all of the sub <ul>s where empty.
<?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml"/> <xsl:output indent="yes"/> <xsl:strip-space elements="*"/>
<xsl:key name="alet" match="//author" use="substring(name/@file-as,1,1)"/>
<!-- <xsl:variable name="letters"> <l>A</l> <l>B</l> <l>C</l> <l>D</l> <l>E</l> </xsl:variable> --> <xsl:template match="/booklist"> <xsl:call-template name="gen-toc"/> </xsl:template>
<!-- Generate Table of Contents --> <xsl:template name="gen-toc"> <div id="toc" class="toc"> <h1>Table of Contents (by Author)</h1> <ul> <xsl:for-each select="UNIQUE-SET-OF-FIRST-LETTERS"> <xsl:variable name="lc" select="."/> <li> <a> <xsl:attribute name="name" select="$lc"/> <xsl:value-of select="$lc"/> </a> <ul> <xsl:for-each select="key('alet',$lc)"> <xsl:sort select="name/@file-as"/> <li> <a href="#{generate-id(.)}"> <xsl:value-of select="name/@file-as"/> </a> </li> </xsl:for-each> </ul> </li> </xsl:for-each> </ul> </div> </xsl:template> </xsl:stylesheet>
Hopefully, I didn't include too much detail.
Any help appreciated. Thanks.
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