Subject: Re: [xsl] How to use generate-id() inside an xsl:function without a node available? From: Florent Georges <darkman_spam@xxxxxxxx> Date: Tue, 27 Feb 2007 21:22:11 +0100 (CET) |
Abel Braaksma wrote: Hi > The issue is this: I have a function that generates some > nodes based on some strings and these nodes must receive a > unique ID/IDREF value. Normally, one would use > generate-id(), but inside a function (or inside anything > that does not have a context node), generate-id() will > fail. The point is that generate-id() is not a random string generator. It generates an ID based on a node, always the same ID for the same node. If you call it without argument, the context item is used (which is indeed not possible in a function definition). If you can't use extension functions nor pass a reference node to the function, I'm afraid you are out of luck here. Regards, --drkm ___________________________________________________________________________ Dicouvrez une nouvelle fagon d'obtenir des riponses ` toutes vos questions ! Profitez des connaissances, des opinions et des expiriences des internautes sur Yahoo! Questions/Riponses http://fr.answers.yahoo.com
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] How to use generate-id() , David Carlisle | Thread | Re: [xsl] How to use generate-id() , Abel Braaksma |
Re: [xsl] How to use generate-id() , Andrew Welch | Date | Re: [xsl] How to use generate-id() , Abel Braaksma |
Month |