RE: [xsl] Calculating cumulative values

["Simon Shutter" <simon@xxxxxxxxxxx>]

I think I may go with 'conventional' solution provided by Andrew, because it
is natively supported by .Net 2 and my data sets are relatively small and
tranformed pretty quickly.  I will look more into FXSL for the longer term.

If I needed to sort the data before I determined the cumulative numbers, how
do I ensure this happens before aggregating the data?

Thanks,

Simon  
 

-----Original Message-----
From: Dimitre Novatchev [mailto:dnovatchev@xxxxxxxxx] 
Sent: February 3, 2007 4:48 PM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Calculating cumulative values

On 2/3/07, Simon Shutter <simon@xxxxxxxxxxx> wrote:
> Thanks, Dimitre.
>
> Two questions -
>
> a) Will this work with .Net 2.0?

No, the two XSLT processors that come as part of  .NET 2.0 (the classes
XslTransform and XslCompiledTransform) only support XSLT 1.0.

However, in a .NET environment one can use Saxon.NET, which is a port of
Saxon 8.x and implements XSLT 2.0.


>
> b) What are the external files : func-scanlDVC.xsl and func-Operators.xsl?

They are part of the FXSL library.

The latest version of FXSL can be checked out from the CVS of the project
at:

   http://sourceforge.net/cvs/?group_id=53841


One can learn more about FXSL from the presentations made at the Extreme
Markup Languages Conference in Montreal 2006 (FXSL 2 -- for XSLT 2.0, and
FXSL 1 -- for XSLT 1.0) here:

 
http://www.idealliance.org/papers/extreme/proceedings/xslfo-pdf/2006/Novatch
ev01/EML2006Novatchev01.pdf

and here:

 
http://www.idealliance.org/papers/extreme/proceedings/xslfo-pdf/2003/Novatch
ev01/EML2003Novatchev01.pdf


Other papers about different important features of FXSL can be found at the
home page of FXSL:

   http://fxsl.sf.net



--
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play





>
> Simon
>
> -----Original Message-----
> From: Dimitre Novatchev [mailto:dnovatchev@xxxxxxxxx]
> Sent: February 3, 2007 2:50 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Calculating cumulative values
>
> On 2/3/07, Andrew Welch <andrew.j.welch@xxxxxxxxx> wrote:
>
> >
> > You can just use XPath here, no need for recursion:
> >
> > <xsl:template match="point">
> >  <xsl:copy>
> >   <xsl:copy-of select="@*"/>
> >   <xsl:attribute name="y2">
> >     <xsl:value-of select="sum(./@y1|preceding-sibling::point[@x =
> > current()/@x]/@y1)"/>
> >   </xsl:attribute>
> >  </xsl:copy>
> > </xsl:template>
>
>
> However evaluating this XPath expression repeatedly is O(N^2) and will
> probably be slow for long lists.
>
> Here is a solution, using the FXSL function
>
>      f:scanl1()
>
> This transformation:
>
> <xsl:stylesheet version="2.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>  xmlns:f="http://fxsl.sf.net/";
>  exclude-result-prefixes="f"
> >
>  <xsl:import href="../f/func-scanlDVC.xsl"/>
>  <xsl:import href="../f/func-Operators.xsl"/>
>
>  <!-- To be applied on testFunc-scanlDVC3.xml -->
>  <xsl:output omit-xml-declaration="yes" indent="yes"/>
>
>
>  <xsl:template match="node()|@*">
>    <xsl:copy>
>      <xsl:apply-templates select="node()|@*"/>
>    </xsl:copy>
>  </xsl:template>
>
>  <xsl:template match="set">
>    <xsl:copy>
>      <xsl:copy-of select="@*"/>
>      <xsl:for-each-group select="point" group-by="@x">
>         <xsl:for-each select="f:scanl1(f:add(), current-group()/@y1)">
>            <point x="{current-group()[1]/@x}" y="{.}"/>
>         </xsl:for-each>
>     </xsl:for-each-group>
>    </xsl:copy>
>  </xsl:template>
> </xsl:stylesheet>
>
> When applied against the originally provided xml document:
>
> <root id="theroot">
>        <set id="1">
>                <point x="1" y1="2" />
>                <point x="1" y1="3" />
>                <point x="1" y1="0" />
>                <point x="1" y1="2" />
>                <point x="1" y1="2" />
>                <point x="2" y1="3" />
>                <point x="2" y1="0" />
>                <point x="2" y1="2" />
>                <point x="3" y1="2" />
>                <point x="3" y1="3" />
>                <point x="3" y1="1" />
>                <point x="3" y1="2" />
>                <point x="3" y1="2" />
>        </set>
>        <set id="2">
>                <point x="1" y1="2" />
>                <point x="1" y1="3" />
>                <point x="1" y1="0" />
>                <point x="1" y1="2" />
>                <point x="2" y1="2" />
>                <point x="3" y1="2" />
>                <point x="3" y1="2" />
>                <point x="3" y1="2" />
>        </set>
>        <set id="n">
>                <point x="1" y1="2" />
>                <point x="1" y1="3" />
>                <point x="1" y1="2" />
>                <point x="2" y1="3" />
>                <point x="2" y1="0" />
>                <point x="2" y1="2" />
>                <point x="3" y1="3" />
>        </set>
> </root>
>
> produces the wanted result:
>
> <root id="theroot">
>   <set id="1">
>      <point x="1" y="2"/>
>      <point x="1" y="5"/>
>      <point x="1" y="5"/>
>      <point x="1" y="7"/>
>      <point x="1" y="9"/>
>      <point x="2" y="3"/>
>      <point x="2" y="3"/>
>      <point x="2" y="5"/>
>      <point x="3" y="2"/>
>      <point x="3" y="5"/>
>      <point x="3" y="6"/>
>      <point x="3" y="8"/>
>      <point x="3" y="10"/>
>   </set>
>   <set id="2">
>      <point x="1" y="2"/>
>      <point x="1" y="5"/>
>      <point x="1" y="5"/>
>      <point x="1" y="7"/>
>      <point x="2" y="2"/>
>      <point x="3" y="2"/>
>      <point x="3" y="4"/>
>      <point x="3" y="6"/>
>   </set>
>   <set id="n">
>      <point x="1" y="2"/>
>      <point x="1" y="5"/>
>      <point x="1" y="7"/>
>      <point x="2" y="3"/>
>      <point x="2" y="3"/>
>      <point x="2" y="5"/>
>      <point x="3" y="3"/>
>   </set>
> </root>
>
>
> --
> Cheers,
> Dimitre Novatchev
> ---------------------------------------
> Truly great madness cannot be achieved without significant intelligence.
> ---------------------------------------
> To invent, you need a good imagination and a pile of junk
> -------------------------------------
> You've achieved success in your field when you don't know whether what
> you're doing is work or play