Subject: Re: [xsl] select distinct From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Sun, 26 Jun 2005 23:34:55 -0700 (PDT) |
Hi, With XSLT 1.0, you can use Muenchian grouping method: With this, you can make groups by Muenchian method, and select 1st element of the group. With XSLT 2.0, you can use distinct-values method .. Regards, Mukul --- -= jay =- <deepsweech@xxxxxxxxx> wrote: > hey huys how would i do like a select distinct for > multiple nodes with > the same value? > > <xtags:forEach > select="//SERVICE[LISTOFLOCATIONS/LOCATION/LOCATIONID='3']"> > This is Number 3 > </xtags:forEach> > > I would like to display "This is Number 3" once. > > thanks, > -- > *-::jay::-* > > ____________________________________________________ Yahoo! Sports Rekindle the Rivalries. Sign up for Fantasy Football http://football.fantasysports.yahoo.com
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
[xsl] select distinct, -= jay =- | Thread | Re: [xsl] select distinct, David Carlisle |
Re: [xsl] select distinct, omprakash . v | Date | Re: [xsl] select distinct, David Carlisle |
Month |