Subject: Re: [xsl] To eliminate duplicate entries From: "X.P.Pratibha :-)" <xp_pratibha@xxxxxxxxxx> Date: Wed, 08 Jun 2005 18:27:19 +0530 |
Hi all Let me give a sample piece of my real problem and I am new to XSL : My XML data is very complex :
<contradictrules> <FWrules> <condradictrule condradict="overlap"> <FWrule id="xxx" ver ="TIM" > <line>5</line> <comment/> <level/> <interval>0<Interval> <permit>true</> <active>true</active> <src><Network id=111"> <Name deleted="false"><![CDATA[any]]>>/Name> </Network> ...... .... <Contadictrules>
Its not difficult to think like this .. If you need more help, please let me know
Regards, Mukul
Hi Mukul, Thanks ... By the by..If my XML data is of the following foramt...
<example> <employee name="ppp"> <empId>111</empId> </employee> <employee name="xxx"/> <empId>222</empId> </employee> <employee name="yyy"/> <empId>111</empId> </employee> </example>
Now what I have to use in the place @name (I guess this for attribute) If my empID is of this type ...
Thanks, Pratibha
Mukul Gandhi wrote:
Or please try this XSL ..
<?xml version="1.0"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="text" />
<xsl:template match="/example">
<xsl:for-each select="employee[not(@name = preceding-sibling::employee/@name)]">
<xsl:value-of select="@name"
/><xsl:text>
</xsl:text>
</xsl:for-each> </xsl:template>
</xsl:stylesheet>
Regards, Mukul
--- "X.P.Pratibha :-)" <xp_pratibha@xxxxxxxxxx>
wrote:
Hi all., I am novoice to XSL .
My XML has multiple Duplicate entries and while
displaying it through
XSL I have to eliminate the multiple duplicate
entries and display
only one entry .
Is there is any way to check the uniqueness of the
data to be
displayed in XSL.
In my xml data say if "employee id" is unqui ,Is
there anyway to check
the replication of employee id in xsl.
Any links or sample code will be of great help.
Thanks, Pratibha
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