Subject: [xsl] Test if an (image) file exists From: "Derek Revill" <derek@xxxxxxxxxxxxxxxxxx> Date: Wed, 8 Jun 2005 12:52:40 +0100 |
Hello, I'd like to test if image files exist in a target directory on my file system before adding links to them in html output (I need to check on $filename.jpg or $filename.gif and other variations.) Should I use a Java extension function in my XSLT or are there now better ways to do this with in-built XSLT functions, using unparsed-text() for example? I'm have an XSLT 2.0 sheet and I'm running Saxon 8.4 (with Java VM 1.4). I'm no Java programmer so an exact code snippet of a template calling Java would be great. I turned up this older example in the archive: http://www.biglist.com/lists/xsl-list/archives/200006/msg01332.html <xsl:template name="file_util_check_directory" xmlns:file="java.io.File"> <xsl:param name="filename" /> <xsl:variable name="directory" select="file:new(file:getParent(file:new($filename)))" /> <xsl:if test="not(file:exists($directory))"> <xsl:choose> <xsl:when test="file:mkdirs($directory)"> <xsl:message> <xsl:text>Creating directory `</xsl:text> <xsl:value-of select="file:getPath($directory)" /> <xsl:text>'</xsl:text> </xsl:message> </xsl:when> <xsl:otherwise> <xsl:message> <xsl:text>WARNING : unable to create directory `</xsl:text> <xsl:value-of select="file:getPath($directory)" /> <xsl:text>'.</xsl:text> </xsl:message> </xsl:otherwise> </xsl:choose> </xsl:if> </xsl:template> <!-- name="file_util_check_directory" --> But if I pass this template a filename (xs:string) I get the following error: "There is more than one method matching the function call file:new, and there is insufficient type information to determine which one should be used." Any help appreciated. Derek -- http://www.revill.demon.co.uk
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