Subject: Re: [xsl] How to find the deepest node? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Fri, 8 Apr 2005 07:00:41 +1000 |
> Using FXSL, one will write something as the following: Or, as a single XPath 2.0 expression: //*[not(*)][count(ancestor::node()) = max(//*[not(*)]/count(ancestor::node())) ] Cheers, Dimitre Novatchev
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] How to find the deepest n, Dimitre Novatchev | Thread | RE: [xsl] How to find the deepest n, Bert |
Re: [xsl] xsl can't get graphic to , JBryant | Date | [xsl] XML Seminars, Ryan Graham |
Month |