Subject: RE: [xsl] Identity Transformations revisited From: "Andreas L. Delmelle" <a_l.delmelle@xxxxxxxxxx> Date: Sat, 6 Mar 2004 20:05:39 +0100 |
> -----Original Message----- > From: Karl J. Stubsjoen > > Why can't I set up a for-each... and transform on each node and > attribute of > the result tree? You *can* but that just wouldn't be the most elegant of solutions... > Maybe I can not push an apply-templates... but Yes you can, however, the snippet below will *only* give you the correct output when there is a corresponding matching template defined. > > A correct template match is made here: > <xsl:template match="campaign"> > <xsl:copy> > <xsl:apply-templates select="@* | node()"/> > </xsl:copy> > </xsl:template> > In short: you also need at least something roughly like the following to go with it <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates /> </xsl:copy> </xsl:template> Hope this helps! Cheers, Andreas XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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