Subject: [xsl] copy part of the original document From: "Stefan Thull" <stefan@xxxxxxxxxx> Date: Mon, 30 Dec 2002 22:52:50 +0100 |
Hello I have a document which has different sections. Each section has an element, called heading. I want to copy the whole document, as it is, except when the heading of a section has an attribute (name="Entwurf"). Then this section and all its children should not be copied. Here is an example: <?xml version="1.0" encoding="UTF-8" ?> <!-- This document was converted from RTF source by upCast Private Edition (c) 1999-2002 <www.infinity-loop.de> --> <document> <documentinfo> <property name="author" value="Stefan Thull" /> <property name="numberOfCharsWS" value="17111" /> </documentinfo> <part> <section level="1"> <heading level="1" name="Title"> Titel</heading> </section> <section level="1"> <heading level="1" name="Entwurf">Ideen: </heading> <section level="2"> <heading level="2" name="Stichwort">Stichwort:</heading> </section> <section level="2"> <heading level="2" name="heading_2"></heading> <Normal>text ... </Normal> <section level="3"> <heading level="3" name="heading_3"> text</heading> <Normal> text text in level 3</Normal> </section> </section> </section> <section level="1"> <heading level="1" name="heading_1"> Thema </heading> <section level="2"> <heading level="2" name="heading_2"> header 2</heading> <Normal> text text text</Normal> </section> </section> </part> ... I have tried it with something like: <xsl:template match="section[heading/@name='Entwurf']"> <xsl:copy-of select=".."> <xsl:apply-templates select="*|@*|processing-instruction()|text()"/> </xsl:copy-of> </xsl:template> <xsl:template match="*|@*|processing-instruction()|text()"/> <xsl:copy> <xsl:apply-templates select="*|@*|processing-instruction()|text()"/> </xsl:copy> </xsl:template> But the parser (4xslt) says, "Illegal child 'xsl:apply-templates' within element 'xsl:copy-of'" Thank you for any help. Stefan Thull XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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