Re: [xsl] xsl filter problem

[Dimitre Novatchev <dnovatchev@xxxxxxxxx>]

Hi Yuval,

> When choosing "all cities" - the result is an empty table instead of 
> the list of all cities with the customers names.
> I tried to giva the param "city" a diect value of "*" or " '*' " and 
> it still didn't work.
> How can I pass a value to this param which will act like : <xsl:for-
> each select="customers/customer[city=*]"> ??


Use:

customers/customer[city=$city or $city = '*']


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL

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