Subject: Re: [xsl] Copying Groups of Attributes From: Oliver Becker <obecker@xxxxxxxxxxxxxxxxxxxxxxx> Date: Tue, 13 Feb 2001 13:21:12 +0100 (MET) |
Oh, a little mistake made by Jeni? > Or you could store the relevant attribute names in a separate XML > structure somewhere, e.g.: > > --- definitions.xml --- > <attgroup name="coreattrs"> > <attribute name="id" /> > <attribute name="class" /> > <attribute name="style" /> > <attribute name="title" /> > </attgroup> > --- > > With the above structure, you could retrieve the list of coreattrs > through something like: > [...] > <xsl:variable name="coreattrs" > select="document('definitions.xml')//attgroup[@name = > 'coreattrs']/attribute" /> > > And then copy all those attributes whose name is equal to one of the > @names of the attribute elements stored in the $coreattrs variable: > > <xsl:template match="p"> > <p> > <xsl:copy-of select="@*[name() = $coreattrs]" /> > </p> > </xsl:template> $coreattrs is a node-set of nodes whose string-value is ... the empty string. You wanted to compare with the name attribute. So either document('definitions.xml')//attgroup[@name = 'coreattrs']/attribute/@name or <xsl:copy-of select="@*[name() = $coreattrs/@name]" /> (Hoping not making another mistake myself ;-) Cheers, Oliver /-------------------------------------------------------------------\ | ob|do Dipl.Inf. Oliver Becker | | --+-- E-Mail: obecker@xxxxxxxxxxxxxxxxxxxxxxx | | op|qo WWW: http://www.informatik.hu-berlin.de/~obecker | \-------------------------------------------------------------------/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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