Subject: Re: [xsl] How to copy all child elements except specific one? From: Dimitre Novatchev <dnovatchev@xxxxxxxxx> Date: Tue, 16 Jan 2001 11:46:23 -0800 (PST) |
Chris, > I assume > > <xsl:copy-of select="" /> > > will do what I need assuming I can come up with the correct select > expression. How do I build an expression that will choose all child elements > except for a specific one? > Use: <xsl:copy-of select="*[not(count(. | $thisChild) = 1)]" /> This can be generalised so that if $thisChild is a node-set containing a subset of children, then this subset will be excluded from copying: <xsl:copy-of select="*[not(count(. | $theseChildren) = count($theseChildren) )]" /> In fact, this is an almost obvious application of the general XPath expression for set difference (ns1 \ ns2): ns1[not(count(. | ns2) = count(ns2))] Dimitre. __________________________________________________ Do You Yahoo!? Get email at your own domain with Yahoo! Mail. http://personal.mail.yahoo.com/ XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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