Subject: Re: [xsl] XPath expression to get the string following the open quote of an attribute? From: "Geert Bormans geert@xxxxxxxxxxxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Thu, 14 Jan 2021 16:33:19 -0000 |
I guess the problem is that this is an attribute value The parses all of that away, I am afraid The attribute value is abc the " would be gone after parsing attribute boundaries can be " or ' if you really need either " or ' and the difference is important, I am afraid you would need a regex step before the XSLT (or read the file as a text file in the XSLT) Met vriendelijke groeten, Best regards, Geert Bormans ----- Op 14 jan 2021 om 17:24 schreef Martin Honnen martin.honnen@xxxxxx xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx: On 14.01.2021 17:14, Roger L Costello costello@xxxxxxxxx wrote: > Here are sample input strings: > > ="abc" > = "abc" > = "abc" > > That is, an equals, zero or more whitespaces, quote, value, quote > > I want everything after the first quote. My neural network thinks that sounds like substring-after($s, '"') but perhaps I miss something that makes the requirements more complicated.
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