Subject: Re: [xsl] Passing parameter into tag name From: "Martin Honnen martin.honnen@xxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 12 Apr 2017 13:11:23 -0000 |
<foo> <Level> <Level_No>1</Level_No> </Level> <Level> <Level_No>2</Level_No> </Level> <Level> <Level_No>3</Level_No> </Level> <Cost ID='1'> <Level_1_Amt>100</Level_1_Amt> <Level_2_Amt>200</Level_2_Amt> <Level_3_Amt>300</Level_3_Amt> </Cost> <Cost ID='2'> <Level_1_Amt>50</Level_1_Amt> <Level_2_Amt>100</Level_2_Amt> <Level_3_Amt>150</Level_3_Amt> </Cost> <Cost ID='3'> <Level_1_Amt>175</Level_1_Amt> </Cost> <Cost ID='4'> <Level_3_Amt>400</Level_3_Amt> </Cost> </foo>
I am trying to sum up the amounts in the following code, but am getting a syntactical error about how I am trying to pass the parameter value into the tag name:
<xsl:stylesheet version="2.0" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema"> <xsl:output method="xml" indent="yes"/>
<xsl:template name="buildLevel"> <xsl:param name="levelNum"/> <Level_Amt> <xsl:value-of select="sum(/Story/Level_{$levelNum}_Amt)"/>
You need to check the name with e.g. sum(/Story/*[local-name() = concat('Level_', $levelNum, '_Amt')])
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