Re: [xsl] Generating a <div>-toggling ID as a variable

["David Maus lists@xxxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx>]

On Mon, 09 Jan 2017 06:33:03 +0100,
Charles Muller acmuller@xxxxxxxxxxxxxxx wrote:
> 
> Writing the javascript and HTML code to toggle one section based on a
> <div> ID is no problem, but in order for each <hom> section of each of
> the many <entry(s)> in the dictionary to be toggled individually, each
> one would need its own separate ID to be generated. I've spent a
> couple of hours researching this, and from what I've found, I'm not
> sure if it's possible.
> 
> The Javascript in the header looks like this:
> 
>               function myFunction(id) {
>               var x = document.getElementById('myDIV');
>               if (x.style.display == 'none') {
>               x.style.display = 'block';
>               } else
>               {
>               x.style.display = 'none';
>               }
>               }
>

The function should use the argument and thus read:

,----
| function myFunction(id) {
|   var x = document.getElementById(id);
|   if (x.style.display == 'none') {
|     x.style.display = 'block';
|   } else
|   {
|     x.style.display = 'none';
|   }
| }
`----

> And the XSLT at the toggle point down below looks like this:
> 
>     <xsl:template match="dictScrap">
>         <p><xsl:apply-templates/></p>
>         <button onclick="myFunction(id);return false;">Show related
> words</button>
> 
>     </xsl:template>
> 
>     <xsl:template match="hom">
>         <div id="myDIV" style="display: none"><xsl:apply-templates/></div>
>     </xsl:template>
>

,----
| <xsl:template match="dictScrap">
|   <p><xsl:apply-templates/></p>
|   <button onclick="myFunction({generate-id(following-sibling::hom)});return false;">Show related words</button>
| </xsl:template>
| 
| <xsl:template match="hom">
|     <div id="{generate-id()}" style="display: none"><xsl:apply-templates/></div>
| </xsl:template>
`----

The first template assumes that there is only one <hom> and the <hom>
is a sibling of the <dictScrap>. You might need to adjust that. The
important part is the use of generate-id(): If you call it with the
same node, it generates the same value.

HTH,
  -- David