Subject: Re: [xsl] Increasing sequence ? From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Wed, 25 Mar 2015 17:36:24 -0000 |
> every $v in 1 to (count($sequence)-1) satisfies ($sequence[$v] lt $sequence[$v+1]) This may be inefficient (depending on the XPath engine being used). I think the following has better chances of being more efficient -- write an xsl:function, name it, say, "increasing". The body of this function can be just: not($seq[2]) or $seq[1] lt $seq[2] and increasing(subsequence($seq, 2)) Cheers, Dimitre On Wed, Mar 25, 2015 at 10:20 AM, Leo Studer leo.studer@xxxxxxxxxxx <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> wrote: > A similar problem as before, is the integer sequence increasing? > > this is my solution: > > every $v in 1 to (count($sequence)-1) satisfies ($sequence[$v] lt $sequence[$v+1]) > > Do you have a better one? > > Cheers > Leo > -- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- Never fight an inanimate object ------------------------------------- To avoid situations in which you might make mistakes may be the biggest mistake of all ------------------------------------ Quality means doing it right when no one is looking. ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play ------------------------------------- To achieve the impossible dream, try going to sleep. ------------------------------------- Facts do not cease to exist because they are ignored. ------------------------------------- Typing monkeys will write all Shakespeare's works in 200yrs.Will they write all patents, too? :) ------------------------------------- I finally figured out the only reason to be alive is to enjoy it.
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