Subject: [xsl] [XSLT 3.0] Question about the simplified syntax of a package From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 9 Nov 2014 21:53:35 -0000 |
In the latest Last Call of the XSLT 3.0 specification (http://www.w3.org/TR/2014/WD-xslt-30-20141002/#packages), we read : "A package that does not itself expose any components or use any library packages may be written using a simplified syntax: the xsl:package element is omitted, and the xsl:stylesheet or xsl:transform element is now the outermost element of the stylesheet module. For compatibility reasons, all the named templates and modes declared in the package are made public. More formally, the principal stylesheet module of the top-level package may be expressed as an xsl:stylesheet or xsl:transform element, which is equivalent to the package represented by the output of the following transformation, preserving the base URI of the source: <xsl:transform version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:t="http://www.w3.org/1999/XSL/TransformAlias"> <xsl:namespace-alias stylesheet-prefix="t" result-prefix="xsl"/> <xsl:template match="xsl:stylesheet|xsl:transform"> <t:package declared-modes="no"> <xsl:copy-of select="@*"/> <t:expose component="mode" names="*" visibility="public"/> <t:expose component="template" names="*" visibility="public"/> <xsl:copy-of select="node()"/> </t:package> </xsl:template> </xsl:transform> " I have two questions: 1. As we see from the code above, only modes and named templates will be exposed in the equivalent xsl:package. Is it correct to conclude that if the principal stylesheet module contains any components of type: function, attribute-set, accumulator, keys and global variables / parameters, these are not exposed and cannot be accessed from a using package? If so, what was the reason for this decision? 2. Because the produced by the transformation above equivalent package doesn't have any "name" or "package-version" attributes specified, how should an <xsl:use-package> in a using package reference the package generated by the transformation? -- Cheers, Dimitre Novatchev
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