Subject: [xsl] Can the default function namespace be undeclared in XSLT? From: "Dimitre Novatchev dnovatchev@xxxxxxxxx" <xsl-list-service@xxxxxxxxxxxxxxxxxxxxxx> Date: Sun, 1 Jun 2014 21:15:53 -0000 |
I want to run the XSLT - analog of the last example (written in XQuery) in section 17.5 of the F & O 3.0 Spec (http://www.w3.org/TR/xpath-functions-30/#constructor-functions-for-user-defined-types): "declare default function namespace ''; apple(17)" However I cannot find any XSLT "default-function-namespace" attribute in the XSLT 3.0 Last Call WD. How can this be done in XSLT 3.0? -- Cheers, Dimitre Novatchev --------------------------------------- Truly great madness cannot be achieved without significant intelligence. --------------------------------------- To invent, you need a good imagination and a pile of junk ------------------------------------- Never fight an inanimate object ------------------------------------- To avoid situations in which you might make mistakes may be the biggest mistake of all ------------------------------------ Quality means doing it right when no one is looking. ------------------------------------- You've achieved success in your field when you don't know whether what you're doing is work or play ------------------------------------- To achieve the impossible dream, try going to sleep. ------------------------------------- Facts do not cease to exist because they are ignored. ------------------------------------- Typing monkeys will write all Shakespeare's works in 200yrs.Will they write all patents, too? :) ------------------------------------- I finally figured out the only reason to be alive is to enjoy it.
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