Subject: [xsl] collection issue, update/rename file From: davep@xxxxxxxxxxxxx Date: Wed, 29 Feb 2012 11:02:19 -0000 |
input a directory full of .xml files running a transform to modify one element, identity transform for the rest. (Yes, I have created a backup) I want to process A.xml, write out A.xml ... somehow (no I'm not on Linux to make it easy) I'm using <xsl:for-each select="collection('file:///Long-path?select=*.xml')"> <xsl:result-document href="???" method="xml" encoding="utf-8" indent="yes"> <xsl:apply-templates/> base-uri(.) returns the full pathname of the source document? Do I have to work with that to obtain A.xml? (text processing....) Is there some way I can obtain the filename.extn? TIA Dave
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