Subject: [xsl] question on random numbers for browser XSLT From: Hermann Stamm-Wilbrandt <STAMMW@xxxxxxxxxx> Date: Wed, 22 Jul 2009 14:43:03 +0200 |
I want random numbers in a stylesheet but I am bound to XSLT 1.0 and not able to make use of "http://exslt.org/random" extensions because the stylesheet should be accessed by <?xml-stylesheet ...?> in a browser XML document. Is there a pure XSLT solution? (the quality of the generated random numbers is not that important) After some playing around I found below (not pure XSLT) solution. Important is that the PERL script lives in the same domain as the stylesheet. You may try it out (random number "0-5") by clicking here: http://stamm-wilbrandt.de/en/xsl-list/random/rand6.xml $ cat rand6.xml <?xml version="1.0" encoding="ISO-8859-1"?> <?xml-stylesheet type="text/xsl" href="rand6.xsl"?> <tag/> $ cat rand6.xsl <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html" encoding="UTF-8"/> <xsl:template match="/"> <xsl:variable name="rand" select="document('/cgi-bin/rand.pl?6')"/> <html><body>rand(6): <xsl:value-of select="$rand"/></body></html>: </xsl:template> </xsl:stylesheet> $ $ cat cgi-bin/rand.pl #!/usr/bin/perl -w. print "Content-type: text/xml\n\n"; printf("<?xml version=\"1.0\"?>\n"); printf("<rand>%d</rand>\n", rand($ARGV[0])); printf("<!-- PERL rand(%d) -->\n",$ARGV[0]); Mit besten Gr|_en / Best wishes, Hermann Stamm-Wilbrandt Developer, XML Compiler WebSphere DataPower SOA Appliances ---------------------------------------------------------------------- IBM Deutschland Research & Development GmbH Vorsitzender des Aufsichtsrats: Martin Jetter Geschdftsf|hrung: Erich Baier Sitz der Gesellschaft: Bvblingen Registergericht: Amtsgericht Stuttgart, HRB 243294
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