Subject: [xsl] calculating relative position in document order From: tom s <tshmit@xxxxxxxxx> Date: Thu, 16 Oct 2008 09:53:33 -0700 (PDT) |
Hi, I'd like to be able to determine which element is "closer", in terms of document order, to a given element. eg, given two structures containing siblings: <a> <b> <c> and <b> <a> <c> I'd like to detect that the second structure is "out of order". In my fantasy pseudo code, I might express the constraint as: //c[positionEX(preceding::a[1]) > positionEX(preceding::b[1])] Where my fantasy positionEX() function returns the absolute position of the argument in the document. Am I missing something, or is implementing this operation in real xpath/xslt much more difficult than it seems it should be? Thanks in advance for any help... --T
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Expensive XSLT2 - suggest, Michael Müller-Hille | Thread | Re: [xsl] calculating relative posi, G. Ken Holman |
Re: [xsl] Expensive XSLT2 - suggest, Wendell Piez | Date | Re: [xsl] calculating relative posi, G. Ken Holman |
Month |