|
Subject: Re: [xsl] xsl:copy- of and namespaces From: Florent Georges <lists@xxxxxxxxxxxx> Date: Tue, 1 Apr 2008 17:19:00 +0200 (CEST) |
Garvin Riensche wrote:
Hi
> Can someone please tell me how I can give elements of a
> subtree that are copied to the output with <xsl:copy-of
> select="."> a new namespace?
The aim of xsl:copy-of is to, well, copy its arguments.
If I understand you right (but that's not sure), you want to
change the namespace URI part of the name of the elements to
copy. So that's not excatly a copy, but a transformation:
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*" priority="0">
<xsl:element name="new:{ local-name(.) }">
<xsl:apply-templates select="@*|node()"/>
</xsl:element>
</xsl:template>
That means: copy everything, except the element nodes, in this case
create a new element node whose the name is the same local-name but in
the new namespace.
Regards,
--drkm
_____________________________________________________________________________
Envoyez avec Yahoo! Mail. Plus de moyens pour rester en contact. http://mail.yahoo.fr
| Current Thread |
|---|
|
| <- Previous | Index | Next -> |
|---|---|---|
| RE: [xsl] xsl:copy- of and namespac, Michael Kay | Thread | Re: [xsl] xsl:copy- of and namespac, Alessandro Bologna |
| RE: [xsl] xsl:copy- of and namespac, Michael Kay | Date | Re: [xsl] xsl:copy- of and namespac, Alessandro Bologna |
| Month |