Subject: Re: [xsl] XSLT Output contains the unwanted content of all elements as text From: Florent Georges <darkman_spam@xxxxxxxx> Date: Thu, 8 Mar 2007 16:27:56 +0100 (CET) |
Michael Kay wrote: Hi > If there's no template in your stylesheet that matches a > given element, then the default template kicks in: this > outputs the text of the element (without any tags). Change > the default by including > <xsl:template match="*"/> With the OP example, that will result in no output at all, as the root element will match this template rule and no other processing will be done. But off course that depends on the whole, real stylesheet of the OP. Maybe the following can help him, too: <xsl:template match="text()"/> Regards, --drkm ___________________________________________________________________________ Dicouvrez une nouvelle fagon d'obtenir des riponses ` toutes vos questions ! Profitez des connaissances, des opinions et des expiriences des internautes sur Yahoo! Questions/Riponses http://fr.answers.yahoo.com
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