Subject: Re: [xsl] Element name Change for a node From: "Mukul Gandhi" <gandhi.mukul@xxxxxxxxx> Date: Thu, 14 Sep 2006 09:50:27 +0530 |
<xsl:template match="/address"> <address> <xsl:apply-templates /> </address> </xsl:template>
<xsl:template match="*[../self::address]"> <xsl:element name="{concat('US_', local-name())}"> <xsl:value-of select="." /> </xsl:element> </xsl:template>
<address> <streetAddress>123 First Street</streetAddress> <city>Sometown</city> <state>CA</state> <zip>12345</zip> <province/> <country>USA</country> </address>
<?xml version="1.0" encoding="UTF-8"?> <address> <US_streetAddress>123 First Street</US_streetAddress> <US_city>Sometown</US_city> <US_state>CA</US_state> <US_zip>12345</US_zip> <US_province/> <US_country>USA</US_country> </address>
Hi All,
I have the following structure in my XML and I want to transform this all "address" node content to prefix with "US". Please let me how to create the XSL template for the given input.
Input <address> <streetAddress>123 First Street</streetAddress> <city>Sometown</city> <state>CA</state> <zip>12345</zip> <province /> <country>USA</country> </address>
output <address> <US_streetAddress>123 First Street</US_streetAddress> <US_city>Sometown</US_city> <US_state>CA<US_/state> <US_zip>12345</US_zip> <US_province /> <US_country>USA</US_country> </address>
I do not know how to create the XSL for it to transform.
Thanks for your help.
Regards, Senthil
-- Regards, Mukul Gandhi
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