Subject: RE: [xsl] looping in increments From: cknell@xxxxxxxxxx Date: Mon, 11 Sep 2006 15:09:52 -0400 |
You cannot change a variable once it has been defined. That is why looping (in the manner of procedural languages) cannot be done in XSLT. To find out how to achieve the results you want, abandon any notion of "for x=1 to 30; ... loop;". Begin by telling us where the different integer values come from. -- Charles Knell cknell@xxxxxxxxxx - email -----Original Message----- From: Vijay Malgari <vmalgari@xxxxxxx> Sent: Mon, 11 Sep 2006 15:03:36 -0400 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] looping in increments Hello All: I did go through the FAQ's list and I could not find any help or to say any lead. Please do ignore if my question is trivial. I have a block of code that I want to repeat for different integer values and I have no clue how to do the increment while looping the same block of xsl code. Here is the code: I want to repeat the same block for all Feature[] values... <xsl:if test="descendant::Feature[1]"> <fo:block-container reference-orientation="90" inline-progression-dimension.minimum="5mm" inline-progression-dimension.optimum="15mm" inline-progression-dimension.maximum="auto"> <fo:block> <xsl:if test="descendant::Attribute"> <xsl:for-each select="descendant::Feature[1]/Attribute"> <fo:block-container reference-orientation="-90" inline-progression-dimension="35mm" width="1.5in"> <fo:block font-size="6.5pt"> <xsl:value-of select="@value"/> </fo:block> </fo:block-container> </xsl:for-each> </xsl:if> </fo:block> </fo:block-container> </xsl:if> Any help/lead is greatly appreciated, Thanks, Vijay
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