Subject: Re: [xsl] sort question From: "Juergen" <xsl@xxxxxxxxxxxxxxx> Date: Fri, 8 Sep 2006 09:40:36 +0200 |
move the select statement one level up. Apply templates gets one "lang"-node. No Use to sort.
<xsl:for-each select="//node()[@xml:lang]"> <xsl:sort select="@xml:lang" order="ascending"/> <xsl:apply-templates select="node() | @*"> </xsl:apply-templates> </xsl:for-each>
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