Subject: Re: [xsl] Sort before paging From: "Giancarlo Rossi" <giancarlo_rossi@xxxxxxxxxx> Date: Mon, 1 Sep 2003 23:10:02 +0200 |
I'm testing your advice but it doesnt works. The xsl file is the following: I'm trying to apply the template without any paging: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <xsl:call-template name="positionfilter"> <xsl:with-param name="sortedlist"> <xsl:for-each select="/CommandList/CheckRouting/RouterList/Router/GroupList/Group/OutwardL ist/Outward" > <xsl:sort select="Price/amount" data-type="number" order="ascending" /> <xsl:copy-of select="."/> </xsl:for-each> </xsl:with-param> </xsl:call-template/> </xsl:template> <xsl:template name="positionfilter"> <xsl:param name="sortedlist"/> <xsl:for-each select="msxsl:node-set($sortedlist)/"> <xsl:text>test</xsl:text> </xsl:for-each> </xsl:template> </xsl:stylesheet> The error is still the same: Not well formed and so on...
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Thread | RE: [xsl] Sort before paging, Mauritz Jeanson | |
Date | [xsl] Sorting By a calculated varia, Giancarlo Rossi | |
Month |