Subject: Re: [xsl] Alternate sort order of subelements based on previous parent element From: "Joris Gillis" <roac@xxxxxxxxxx> Date: Thu, 01 Sep 2005 09:13:54 +0200 |
Hi, Tempore 03:00:25, die 09/01/2005 AD, hinc in xsl-list@xxxxxxxxxxxxxxxxxxxxxx scripsit Philipp Kursawe <LukeSky77@xxxxxxx>:
I have run into a problem solving the following sophisticated (at least for me) task: There is a list of items each containing two nodes "row" and "col". First the list has to be ordered ASCENDING by "rows". Next step is to sort the list items of each "row" by its "col" node where the ordering direction changes when the row is different to the previous.
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="items"> <xsl:copy> <xsl:for-each select="item[generate-id(key('item',@row))=generate-id()]"> <xsl:sort select="@row" data-type="number"/> <xsl:variable name="order"> <xsl:choose> <xsl:when test="position() mod 2=0">ascending</xsl:when> <xsl:otherwise>descending</xsl:otherwise> </xsl:choose> </xsl:variable> <xsl:comment><xsl:value-of select="$order"/></xsl:comment> <xsl:for-each select="key('item',@row)"> <xsl:sort select="@col" order="{$order}" data-type="number"/> <xsl:copy-of select="."/> </xsl:for-each> </xsl:for-each> </xsl:copy> </xsl:template>
regards, -- Joris Gillis (http://users.telenet.be/root-jg/me.html) B+There are only 10 types of people in this world. Those who understand binary, and those who don'tB;
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