Subject: [xsl] Generating table cells and rows From: Aaron Johnson <artpunx@xxxxxxxxx> Date: Mon, 1 Aug 2005 11:08:33 +0100 |
Hello... I have a stylesheet that outputs a series of photographs from an xml list. <xsl:template name="displayPhotos"> <xsl:param name="currentNodes"/> <xsl:for-each select="$currentNodes"> <img src="{$photo_server}/?studentId={id}"/><br /> Name: <xsl:value-of select="name"/> <xsl:if test="position() mod 5 =0"><br/></xsl:if> </xsl:for-each> </xsl:template> The template adds a line break for eack 5 images. I would like to know if there is a way to do this with a table? Is it possible to output 5 table cells and add another <tr> tag if required for a second row of images? Any ideas would be most appreciated. Aaron
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