Subject: Re: [xsl] Grouping problem From: David Carlisle <davidc@xxxxxxxxx> Date: Mon, 1 Aug 2005 10:00:32 +0100 |
You are right.. This means, we cannot solve this problem with precedings-sibling axis. Or rather, you just need to structure things to access all the nodes in the set, eg <xsl:for-each select="*"> <xsl:if test="not(preceding-sibling::*[name()=name(current())])"> ... or use key (muenchian) grouping which is usually more efficient anyway. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Grouping problem, Mukul Gandhi | Thread | RE: [xsl] Grouping problem, Michael Kay |
RE: [xsl] Grouping problem, Michael Kay | Date | Re: [xsl] xsl:apply-templates doesn, David Carlisle |
Month |