[xsl] Node position and numbering.

[c p <bugs75il@xxxxxxxxx>]

Hello all,

I have following XML:
-----------------------------------------

<?xml version="1.0" encoding="UTF-8"?>
<service>
    <title>Printing the Page</title>
    <somenode>node content might go here.</somenode>
    <step>Go to File menu</step>
    <step>Select Print</step>
    <step>Click Print</step>
    <somenode>you are all done.</somenode>
</service>

-----------------------------------------
As you can see the XML has a <service> node with a
whole bunch of other child nodes.  Out of all the
child nodes, I am interested in getting the position
for <step> nodes only.  Its pretty simple but there's
a twist.  In the example above if I did
<xsl:apply-templates match="service"/>  and then for
each child node I did a position() then it would give
me numbers 2,4,and 5 for the <step> nodes.  However
thats not what I want.  I want it to give me numbers
1,2,3 for the <step> nodes.  The way I can get that is
by doing <xsl:apply-templates match="service/step"/>,
unfortunately due to the complexity of my XSL and XML
structure I cannot do that.  Is there a way to achieve
this so I can get an output that will look like this:

---------------------------------------------
1. Go to File menu
2. Select Print
3. Click Print
---------------------------------------------

Note:  Its not always guaranteed that the first <step>
node will start after <title> node or any other node. 
It could be random.

Any help would be appreciated.

Thx,
C



__________________________________________________
Do You Yahoo!?
Tired of spam?  Yahoo! Mail has the best spam protection around 
http://mail.yahoo.com