Subject: [xsl] filtering elements using identity transform From: omprakash.v@xxxxxxxxxxxxx Date: Thu, 31 Mar 2005 13:43:14 +0530 |
Hi, You were right. There was an xmlns in my xhtml input and Iam surprised nobody saw it because it was there in the xhtml snippet I posted yesterday. Anyways, like I said earlier, Iam embedding my xml inside the html as I have a need to go back and forth between the xml and html format to which I am transforming the xml. So, I thought I'd write an inverse transform that will just give me back my xml. But does this mean that the input xhtml should not be bound to any namespace. I have found that the "xmlns:" in my slideshow element is what's causing the html to appear in my result. My xhtml snippet looks like <html> <head> </head> <body> <p> <table> <tr> <slideshow author="Yours Truly" title="Sample Slide Show" date ="Date of publication" xmlns="urn:hl7-org/v3"> <td> </td> And my stylesheet <xsl:output method="xml" indent="yes" /> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> <xsl:template match="table"> <xsl:apply-templates/> </xsl:template> <xsl:template match="html"> <xsl:apply-templates/> </xsl:template> etc How do I make this work without having to remove the namespace declaration in my original xml. Cheers, Omprakash.V This e-Mail may contain proprietary and confidential information and is sent for the intended recipient(s) only. If by an addressing or transmission error this mail has been misdirected to you, you are requested to delete this mail immediately. You are also hereby notified that any use, any form of reproduction, dissemination, copying, disclosure, modification, distribution and/or publication of this e-mail message, contents or its attachment other than by its intended recipient/s is strictly prohibited. Visit Us at http://www.polaris.co.in
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