Subject: RE: [xsl] replacement example , help From: "Aron Bock" <aronbock@xxxxxxxxxxx> Date: Tue, 29 Mar 2005 16:51:07 +0000 |
From: henry human <henry_human@xxxxxxxx> Reply-To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] replacement example , help Date: Tue, 29 Mar 2005 13:01:06 +0200 (CEST)
hello, In this xsl styesheet i will replace aa with the string cc, what do i wrong ,that i dont get cc? thank you to have a look on this stylesheet:
<?xml version="1.0"?> <?xml-stylesheet type="text/xsl" href="replace.xsl"?>
<document> <part1> <name>uaabb</name> </part1> </document>
------------
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="html"/>
<xsl:template name="part1"> <xsl:param name="name"/> <xsl:param name="aa"/> <xsl:param name="cc"/> <xsl:choose> <xsl:when test="contains($name,$aa)"> <xsl:value-of select="substring-before($name,$aa)"/> <xsl:value-of select="$cc"/>
<xsl:call-template name="part1"> <xsl:with-param name="name" select="substring-after($name,$aa)"/> <xsl:with-param name="aa" select="$aa"/> <xsl:with-param name="cc" select="$cc"/> </xsl:call-template>
</xsl:when>
<xsl:otherwise> <xsl:value-of select="$name"/> </xsl:otherwise>
</xsl:choose>
</xsl:template>
</xsl:stylesheet>
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