Subject: [xsl] newbie question concerning javascript and xsl. From: Lior Kesos <lior.kesos@xxxxxxxxx> Date: Wed, 2 Mar 2005 17:52:27 +0200 |
I have a "classic" xml xsl and javascript environment in which all of the elements are on different files. My index.html loads the xml and xsl succssfully and renders a table which you can see below. <xsl:for-each select="CHANNEL[SERVER = 'db2srv1']"> <xsl:sort select="name"/> <tr> <xsl:if test="META = 'enterprise'"> <td class="enterprise" onclick="submit_channel(this.innerHTML)"><xsl:value-of select="EXTENSION"/></td> </xsl:if> <xsl:if test="META = 'community'"> <td class="community" onclick="submit_channel(this.innerHTML)"><xsl:value-of select="EXTENSION"/></td> </xsl:if> </tr> </xsl:for-each> I know that the this.innerHTML is wrong but I can't figure out how to pass the EXTENSION parameter to the javascript. The closest I got to was if I put submit_channel({.}) which I saw in some sniplet. I have been trying to read this until solution but after 2 days of googling and trying different approaches I'm consulting with the pros... any help will be appriciated. Lior. -- Peace Love and Penguins - Lior Kesos
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Sorting network addresses, Craig W | Thread | Re: [xsl] newbie question concernin, Emmanouil Batsis |
RE: [xsl] Retrieving Parameters Val, Pieter Reint Siegers | Date | Re: [xsl] Retrieving Parameters Val, Emmanouil Batsis |
Month |