Subject: Re: [xsl] condition problem From: Mukul Gandhi <mukul_gandhi@xxxxxxxxx> Date: Wed, 6 Oct 2004 08:05:34 -0700 (PDT) |
Hi Dusan, This problem requires eliminating duplicates, and can be solved using Muenchian technique - <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="text" /> <xsl:key name="by-ge" match="SI" use="concat(G,E)" /> <xsl:template match="/"> <xsl:for-each select="//SI[generate-id(.) = generate-id(key('by-ge', concat(G,E))[1])]"> <xsl:value-of select="G" /><xsl:value-of select="E" /><xsl:text>
</xsl:text> </xsl:for-each> </xsl:template> </xsl:stylesheet> Regards, Mukul --- Dusan Zatkovsky <zatkovsky@xxxxxxxxxxxx> wrote: > Hi. > > I have this document: > > <data> > <A> > <SI> > <G>1</G> > <E>1</E> > <value>123</value> > </SI> > <SI> > <G>1</G> > <E>2</E> > <value>456</value> > </SI> > <SI> > <G>2</G> > <E>2</E> > <value>678</value> > </SI> > </A> > > <B> > <SI> > <G>2</G> > <E>1</E> > <value>123</value> > </SI> > <SI> > <G>1</G> > <E>2</E> > <value>123</value> > </SI> > > </B> > </data> > > > I want to create for-each cycle, merging SIs from A > and B. > > When I have test for-each select="data/A/SI | > data/B/SI", result is > (G/E): > 1 1 > 1 2 > 2 2 > 2 1 > 1 2 > and 1 2 are twice. > > How to create cycle, which result will be: > 1 1 > 1 2 > 2 2 > 2 1 > > I have tried condition (data/A/SI/G=data/B/SI/G and > data/A/SI/E=data/B/SI/E), but it returns true, > because B/SI/G=1 was > found in A/SI[1], A/SI[2] and B/SI/E=2 was found in > A/SI[2] and > A/SI[3]. > > I want to compare exactly G+E in one SI, not over > all. > > Thank you. > > > -- > > Dusan Zatkovsky __________________________________ Do you Yahoo!? Yahoo! Mail Address AutoComplete - You start. We finish. http://promotions.yahoo.com/new_mail
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