Subject: RE: [xsl] template matching From: Peter Flynn <pflynn@xxxxxx> Date: Fri, 06 Feb 2004 14:04:01 +0000 |
On Thu, 2004-02-05 at 15:52, Varley, Roger wrote: > > > > On Wed, 2004-02-04 at 14:51, Varley, Roger wrote: > > > > > > > > <xsl:template match="//note"> > > > > <li> > > > > <xsl:apply-templates/> > > > > </li> > > > > </xsl:template> > > > > > > > > > > Oh rats! Just when I thought I'd got my head around XSLT. > > > > Gin and tonic required? > > > > > Would you explain why this works, in particular why it prints only > > > the values of the <note> elements > > > > Because that's what it says it will do. The template > > will match every note in the document, at any depth > > or location, and for each one, output a LI element > > containing the value of the note. > > Sorry - I wasn't being very clear. I was suprised to get output without an <xsl:value-of select="."/> The default (in the absence of any matching template) is to output the content. value-of is useful for out-of-line processing, or putting a value in more than one place in the output tree, or handling attributes. It's not needed when all you want is the default: the character data content. > > > > > and no blank lines for the <sub1> <sub2 .... elements > > > > Because there's nothing there to do that. Where did you > > want space to appear? > > > > I was expecting the standard default template to be invoked for the <sub1> <sub2> elements because there is no template provided to match them. What is the "standard default template" you refer to? If you mean the one I just mentioned, then it *is* being invoked...just that there is nothing to output, only further elements to match. ///Peter XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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